Completed Graph-1

[Sanket-S-Kale]

No description provided.

[super30admin]

Find the Town Judge (Problem1.py)

Excellent work! Your solution is correct, efficient, and well-documented. Here are some specific strengths:

1. Clear comments: Your inline comments effectively explain the logic behind each operation, making the code very readable.
2. Good variable naming: Using trustee and trusted makes the intent of the code immediately clear.
3. Complexity analysis: Including the time and space complexity analysis in comments is a great practice.
4. Correct approach: Using net trust score (in-degree minus out-degree) is the optimal approach for this problem.

Minor suggestions for future improvements:

• Consider adding a brief docstring for the findJudge method to describe its purpose and parameters.
• The comment "trusts someone, violating judge property 2" is slightly misleading - it should reference property 1 (judge trusts nobody) since the trustee is the one who trusts someone.

Overall, this is a high-quality solution that demonstrates strong understanding of the problem and efficient algorithm design.

VERDICT: PASS

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The Maze (Problem2.py)

Strengths:

• Clean DFS implementation that's easy to understand
• Correct rolling logic that properly handles walls and boundaries
• Good use of type hints for readability
• The visited marking prevents infinite loops

Areas for Improvement:

1. Avoid modifying input: Consider using a separate visited set or matrix instead of modifying the input maze. This makes the function more reusable and avoids surprising side effects.
2. Early termination optimization: You could check if the current position is the destination before marking it as visited, which you're already doing - good!
3. Consider iterative DFS: For very large mazes, recursive DFS could hit Python's recursion limit. An iterative approach with an explicit stack would be more robust.
4. Minor optimization: The visited check at the start of the function is good, but you could potentially avoid some rolling work by checking visited status before rolling in each direction.

Overall, this is a solid solution that correctly solves the problem with good code quality.

VERDICT: PASS