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Completed DFS-1 - #2017

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Completed DFS-1#2017
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Coin Change (CoinChange.java)

Strengths:

  • Correct implementation of bottom-up DP
  • Good use of sentinel value (amount + 1) to represent infinity
  • Clear comments explaining the approach
  • Well-structured and readable code
  • Significantly better time complexity than the reference solution

Areas for improvement:

  • Consider optimizing space complexity to O(amount) using a 1D DP array. The recurrence dp[i][j] = min(dp[i-1][j], dp[i][j - coins[i-1]] + 1) only depends on the current row and the same row at a smaller column, so you can reuse a single array.
  • The variable name coins[i - 1] is used multiple times - extracting it to a local variable could improve readability slightly.

VERDICT: PASS


House Robber (HouseRobber.java)

Great work on your solution! Your dynamic programming approach is correct and significantly more efficient than the recursive approach in the reference solution. Here are some observations:

Strengths:

  1. Optimal Time Complexity: Your O(n) solution is much better than the reference's O(2^n) approach.
  2. Clear Comments: Your comments effectively explain the DP approach and recurrence relation.
  3. Edge Case Handling: You correctly handle the case when there's only one house.
  4. Clean Code: The code is readable and well-organized.

Areas for Improvement:

  1. Space Optimization: You could reduce space complexity from O(n) to O(1) by using just two variables to track the previous two DP values:
    class Solution {
        public int rob(int[] nums) {
            if(nums.length == 1) return nums[0];
            int prev2 = nums[0];
            int prev1 = Math.max(nums[0], nums[1]);
            for(int i = 2; i < nums.length; i++) {
                int curr = Math.max(prev1, nums[i] + prev2);
                prev2 = prev1;
                prev1 = curr;
            }
            return prev1;
        }
    }
  2. Variable Naming: Consider using more descriptive variable names like rob instead of dp to better convey the meaning.

Overall, this is an excellent solution that demonstrates strong understanding of dynamic programming!

VERDICT: PASS

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