Binary Search 2

[YogeshPardeshi]

No description provided.

[super30admin]

Find the First and Last Position of an Element in given Sorted Array (Problem1.java)

Strengths:

• Your solution is functionally correct and handles all edge cases properly.
• The binary search implementation is clean and follows the standard pattern.
• Good use of private helper methods to separate concerns.
• Clear variable naming makes the code readable.
• Efficient use of the first occurrence index to narrow the search range for the last occurrence.

Areas for Improvement:

• Consider adding comments explaining the binary search logic, especially the conditions for finding first/last occurrence.
• The code could benefit from early return optimization in binarySearchLast by checking if the element at first is actually the last occurrence (though this is a minor optimization).

Overall, your implementation is solid and matches the reference solution in both approach and quality.

VERDICT: PASS

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Find the Minimum Element in a Rotated Array(sorted) (Problem2.java)

Strengths:

• Clean, well-structured binary search implementation
• Proper handling of edge cases (array not rotated, single element)
• Good use of comments explaining the logic
• Correct boundary condition checks
• Proper use of mid == 0 and mid == n-1 guards to prevent index out of bounds

Areas for Improvement:

• The fallback return value of -1 could be replaced with a more descriptive error handling approach, though for this problem it will never be reached
• Variable naming could be slightly more descriptive (e.g., left and right instead of low and high for readability)
• Consider adding a brief comment explaining the key insight: the minimum is the only element smaller than its neighbors in a rotated sorted array

The solution is functionally equivalent to the reference and demonstrates solid understanding of binary search on rotated arrays.

VERDICT: PASS

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Find the Peak Element (Problem3.java)

Strengths:

• Correctly implements binary search for peak finding
• Properly handles boundary conditions (mid == 0 and mid == n-1)
• Clean, readable code structure
• Variable naming is clear and consistent
• Time complexity is O(log n), matching the reference solution
• Space complexity is O(1), matching the reference solution

Areas for Improvement:

• Consider adding a bounds check mid < n - 1 in the else-if condition for defensive programming, even though the current logic is safe (the peak check would catch mid == n-1 first)
• Could add early return for edge cases (single element or two elements) for slight optimization, though not required

The solution is functionally correct and follows good coding practices. It is essentially equivalent to the reference solution.

VERDICT: PASS