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Some of the style check complains "WARNING:UNNECESSARY_ELSE: else is not generally useful after a break or return".
N-R-K
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Aug 18, 2022
| else | ||
| options->optarg = 0; | ||
| return option[0]; | ||
| default: { |
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it's not possible for optparse_argtype() to return anything other than -1 .. 2, so this case will never execute.
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Logically yes, but I encountered one case that returned 0 from line 263. I will come back to you if I can reproduce the problem.
By the way, isn't it so that optparse should return one of follwing values?
- Option character, when an option is successfully parsed
- -1: indicate all options have been parsed
'?': for invalid option
The return 0 in line 263 doesn't make that much sense?
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