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17 changes: 15 additions & 2 deletions Sprint-2/improve_with_caches/fibonacci/fibonacci.py
Original file line number Diff line number Diff line change
@@ -1,4 +1,17 @@
#initialising a dictionary to store a copy of what we already know or have already computed
#caching reduces the fibonacci time complexity from exponential to linear.
cache = {}

def fibonacci(n):
if n <= 1:
if n in cache:
return cache[n]

if n <= 1: #when n is 0 or 1, we don’t need to calculate anything,just return th known value
return n
return fibonacci(n - 1) + fibonacci(n - 2)

result = fibonacci(n - 1) + fibonacci(n - 2)

#saving result in our dict before returning
cache[n] = result
return result

22 changes: 19 additions & 3 deletions Sprint-2/improve_with_caches/making_change/making_change.py
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@cjyuan cjyuan Feb 22, 2026

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Array creation is a relatively costly operation.

From line 42, we know coins can only be one of the following 9 arrays:

[200, 100, 50, 20, 10, 5, 2, 1]
[100, 50, 20, 10, 5, 2, 1]
[50, 20, 10, 5, 2, 1]
...
[1]
[]

We could further improve the performance if we can

  • avoid repeatedly creating the same sub-arrays at line 42 (e.g. use another cache), and
  • create key as (total, a_unique_integer_identifying_the_subarray) instead of as (total, tuple of coins)
    • There are only a small number of different subarrays. We can easily assign each subarray a unique integer.

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  1. Thanks for the suggestion . I’ve updated the implementation so I no longer slice the coins list. Instead, I pass a start_index through the recursion, which avoids creating new subarrays entirely.
  2. I also switched the cache key to (total, start_index) rather than (total, tuple(coins)). This gives each of the 9 possible sub‑arrays a unique integer “identity” automatically, without needing a separate mapping
  3. This keeps the logic the same but removes the repeated list allocations and makes the memoisation faster and cheaper.

Original file line number Diff line number Diff line change
@@ -1,5 +1,5 @@
from typing import List

cache = {}

def ways_to_make_change(total: int) -> int:
"""
Expand All @@ -11,22 +11,38 @@ def ways_to_make_change(total: int) -> int:


def ways_to_make_change_helper(total: int, coins: List[int]) -> int:

"""
Helper function for ways_to_make_change to avoid exposing the coins parameter to callers.
"""
if total == 0 or len(coins) == 0:
#We found one valid way if its an exact match.
if total == 0:
return 1
#base case no coins left but still have remaining total but no way to form it
if not coins:
return 0
#creating a cache key from our current prob, converting list to a tuple to make it hashable
key = (total, tuple(coins))
if key in cache:
return cache[key]


ways = 0
# Try using the current coin 1,2,3...times as long as we don't exceed the total.
for coin_index in range(len(coins)):
coin = coins[coin_index]
count_of_coin = 1
while coin * count_of_coin <= total:
total_from_coins = coin * count_of_coin
if total_from_coins == total:
if total_from_coins == total: #if we get an exact match ++ on ways
ways += 1

#remaining total and remaining coins after using the current one
else:
intermediate = ways_to_make_change_helper(total - total_from_coins, coins=coins[coin_index+1:])
ways += intermediate

count_of_coin += 1
cache[key] = ways
return ways

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