first commit#1
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Barrakuda8 wants to merge 3 commits into
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| print(check_1(lst)) | ||
| print(check_2(lst)) | ||
| print(check_3(lst)) |
| user_list = [2, 3, 4, 10, 1, 8] | ||
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| print(min_n2(user_list)) | ||
| print(min_n(user_list)) No newline at end of file |
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| print(max3_1(companies)) | ||
| print(max3_2(companies)) | ||
| print(max3_3(companies)) No newline at end of file |
| """ | ||
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| def check_1(dct): # O(бесконечность) - цикл while True |
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O(бесконечность) - у нас есть такая сложность?
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такой сложности нет, но какая тогда должна быть сложно у цикла while True? и он считается линейным циклом, потому что n - количество его итераций?
| break | ||
| else: | ||
| answer = input('Хотите активировать учётную запись?: ') | ||
| if answer.lower() == 'да': |
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O(n^2) - n * n
уверены?
проставьте сложности кажждого выражения
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слишком быстро смотрел. очевидно цикл константный, а значит сложность итоговая - линейная
| for _ in range(7): | ||
| stack.pop_out() | ||
| print(stack.get_quantity()) | ||
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| to_rework.from_queue().is_done() | ||
| print(to_do) | ||
| print(to_rework) | ||
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| return still_equal | ||
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| print(pal_checker("молоко делили ледоколом")) No newline at end of file |
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