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Exercise_2.java
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// Time Complexity : O(nlog n) best and average case , O(n^2) worst case
// Space Complexity : O(n) worst case
// Your code here along with comments explaining your approach
/*
* The idea is to find a specific partition index and sort using it for first and second halfs recursively
* But, to choose this partition, I need to understand the order of the elements. So, I assume a pivot
* element first, then try to compare iteratively each element of the array with pivot and make sure to
* place/swap all those smaller elements to left side of the array in comparison with pivot. then, I return
* that least index element which acts as a partition of smaller sorted elements till now and the rest.
* */
class QuickSort
{
/* This function takes last element as pivot,
places the pivot element at its correct
position in sorted array, and places all
smaller (smaller than pivot) to left of
pivot and all greater elements to right
of pivot */
void swap(int arr[],int i,int j){
//Your code here
int temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
}
int partition(int arr[], int low, int high)
{
//Write code here for Partition and Swap
int i = low - 1;
int pivot = arr[high];
for(int j = low ; j <= high - 1 ; j++) {
if(arr[j] < pivot) {
i++;
swap(arr, i, j);
}
}
swap(arr, i + 1, high);
return i + 1;
}
/* The main function that implements QuickSort()
arr[] --> Array to be sorted,
low --> Starting index,
high --> Ending index */
void sort(int arr[], int low, int high)
{
// Recursively sort elements before
// partition and after partition
if(low < high) {
int pi = partition(arr, low, high);
sort(arr, low, pi - 1);
sort(arr, pi + 1, high);
}
}
/* A utility function to print array of size n */
static void printArray(int arr[])
{
int n = arr.length;
for (int i=0; i<n; ++i)
System.out.print(arr[i]+" ");
System.out.println();
}
// Driver program
public static void main(String args[])
{
int arr[] = {10, 7, 8, 9, 1, 5};
int n = arr.length;
QuickSort ob = new QuickSort();
ob.sort(arr, 0, n-1);
System.out.println("sorted array");
printArray(arr);
}
}