-
Notifications
You must be signed in to change notification settings - Fork 2.6k
Expand file tree
/
Copy pathExercise_3.py
More file actions
85 lines (66 loc) · 1.88 KB
/
Exercise_3.py
File metadata and controls
85 lines (66 loc) · 1.88 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
class ListNode:
"""
A node in a singly-linked list.
"""
def __init__(self, data, next=None):
self.data = data
self.next = next
class SinglyLinkedList:
def __init__(self):
"""
Create a new singly-linked list.
Takes O(1) time.
"""
self.head = None
def append(self, data):
if self.head == None:
self.head = ListNode(data)
return
curr = self.head
while curr.next:
curr = curr.next
curr.next = ListNode(data)
"""
Insert a new element at the end of the list.
Takes O(n) time.
"""
def find(self, key):
curr = self.head
while (curr):
if (curr.data == key):
return curr
curr = curr.next
return None
"""
Search for the first element with `data` matching
`key`. Return the element or `None` if not found.
Takes O(n) time.
"""
def remove(self, key):
if self.head and self.head.data == key:
temp = self.head
self.head = self.head.next
temp.next = None
return
curr = self.head
while curr and curr.next:
if (curr.next.data == key):
temp = curr.next
curr.next = curr.next.next
temp.next = None
return
curr = curr.next
return None
"""
Remove the first occurrence of `key` in the list.
Takes O(n) time.
"""
def print_list(self):
curr = self.head
if curr is None:
print("List is empty")
return
while curr:
print(curr.data, end=" -> ")
curr = curr.next
print("None")