diff --git a/Problem1.py b/Problem1.py
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+## Problem1 Find Judge (https://leetcode.com/problems/find-the-town-judge/)
+# Time Complexity: O(N + E)
+# - We iterate through the trust array of size E once to compute net degrees: O(E).
+# - We iterate through the range from 1 to N to find the town judge: O(N).
+# - Overall Time Complexity: O(N + E), where N is the number of people and E is the number of trust relationships.
+#
+# Space Complexity: O(N)
+# - We create an array 'indegrees' of size (N + 1) to track the net trust score for each person: O(N).
+
+class Solution:
+    def findJudge(self, n: int, trust: List[List[int]]) -> int:
+        # Array to track net trust count (In-degree minus Out-degree) for people 1 through n
+        indegrees = [0] * (n + 1)
+
+        # For every trust relationship [a, b]:
+        # 'a' trusts 'b', so 'a' loses 1 point (trusts someone, violating judge property 2)
+        # 'b' gains 1 point (is trusted by someone, building towards judge property 1)
+        for trustee, trusted in trust:
+            indegrees[trustee] -= 1
+            indegrees[trusted] += 1
+
+        # Check each person from 1 to n
+        # The judge trusts nobody (-0 out-degree) and is trusted by everyone else (+(n - 1) in-degree),
+        # yielding a net score of exactly n - 1.
+        for i in range(1, n + 1):
+            if indegrees[i] == n - 1:
+                return i
+
+        # If no person satisfies the judge condition, return -1
+        return -1
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diff --git a/Problem2.py b/Problem2.py
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+## Problem2 The Maze (https://leetcode.com/problems/the-maze/)
+def has_path(maze: list[list[int]], start: list[int], destination: list[int]) -> bool:
+    rows, cols = len(maze), len(maze[0])
+    directions = [[0, 1], [0, -1], [1, 0], [-1, 0]]
+    
+    def dfs(r: int, c: int) -> bool:
+        # If this stopping position was already visited, skip it
+        if maze[r][c] == 2:
+            return False
+            
+        # Check if we reached the destination stopping point
+        if r == destination[0] and c == destination[1]:
+            return True
+            
+        # Mark current stopping position as visited
+        maze[r][c] = 2
+        
+        # Try rolling in all 4 directions
+        for dr, dc in directions:
+            nr, nc = r, c
+            
+            # Keep rolling until hitting a wall (1) or boundary
+            while 0 <= nr + dr < rows and 0 <= nc + dc < cols and maze[nr + dr][nc + dc] != 1:
+                nr += dr
+                nc += dc
+                
+            # Recursively explore from the stopped position
+            if dfs(nr, nc):
+                return True
+                
+        return False
+
+    return dfs(start[0], start[1])
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