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3SumClosest.cpp
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39 lines (35 loc) · 1.08 KB
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//Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target.Return the sum of the three integers.You may assume that each input would have exactly one solution.
//
//For example, given array S = { -1 2 1 - 4 }, and target = 1.
//
//The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
#include<vector>
#include<algorithm>
using namespace std;
class _3SumClosest {
public:
int threeSumClosest(vector<int>& nums, int target) {
if (nums.size() < 3) return 0;
int closest = nums[0] + nums[1] + nums[2];
sort(nums.begin(), nums.end());
for (int first = 0; first < nums.size() - 2; ++first) {
if (first > 0 && nums[first] == nums[first - 1]) continue;
int second = first + 1;
int third = nums.size() - 1;
while (second < third) {
int curSum = nums[first] + nums[second] + nums[third];
if (curSum == target) return curSum;
if (abs(target - curSum)<abs(target - closest)) {
closest = curSum;
}
if (curSum > target) {
--third;
}
else {
++second;
}
}
}
return closest;
}
};