Tidy up the loop in check_overlapping_overloads, reducing the None checking by preparing the list of valid items

Author: pelson

mypy/checker.py

@@ -913,37 +913,24 @@ def check_overlapping_overloads(self, defn: OverloadedFuncDef) -> None:
 
         is_descriptor_get = defn.info and defn.name == "__get__"
 
-        # Pre-extract callable types and literal fingerprints for each overload item.
-        item_sigs: list[CallableType | None] = []
-        item_literal_fingerprints: list[LiteralFingerprint] = []
-        for item in defn.items:
-            assert isinstance(item, Decorator)
-            sig = self.extract_callable_type(item.var.type, item)
-            item_sigs.append(sig)
-            item_literal_fingerprints.append(
-                build_literal_fingerprint(sig) if sig is not None else {}
-            )
-
+        # Pre-extract callable types and literal fingerprints for each overload
+        # item, skipping items whose signature could not be extracted.
+        # Each entry is (original 0-based index, Decorator, sig, fingerprint).
+        prepared_items: list[tuple[int, Decorator, CallableType, LiteralFingerprint]] = []
         for i, item in enumerate(defn.items):
             assert isinstance(item, Decorator)
-            sig1 = item_sigs[i]
-            if sig1 is None:
-                continue
-
-            for j, item2 in enumerate(defn.items[i + 1 :], i + 1):
-                assert isinstance(item2, Decorator)
-                sig2 = item_sigs[j]
-                if sig2 is None:
-                    continue
+            sig = self.extract_callable_type(item.var.type, item)
+            if sig is not None:
+                prepared_items.append((i, item, sig, build_literal_fingerprint(sig)))
 
+        for prepared_items_i, (i, item, sig1, literals_fingerprint1) in enumerate(prepared_items):
+            for j, item2, sig2, literals_fingerprint2 in prepared_items[prepared_items_i + 1 :]:
                 if not are_argument_counts_overlapping(sig1, sig2):
                     continue
 
                 # If there is any argument position where both overloads
                 # carry a LiteralType with different values they are disjoint.
-                if literal_args_are_disjoint(
-                    item_literal_fingerprints[i], item_literal_fingerprints[j]
-                ):
+                if literal_args_are_disjoint(literals_fingerprint1, literals_fingerprint2):
                     continue
 
                 if overload_can_never_match(sig1, sig2):
@@ -8983,24 +8970,10 @@ def detach_callable(typ: CallableType, class_type_vars: list[TypeVarLikeType]) -
 # Using type(value) as part of the key means Literal[1] (int) and
 # Literal[True] (bool) are kept distinct even though 1 == True in Python.
 # A union such as Literal["a", "b"] or Literal["a"] | Literal["b"] produces
-# a frozenset of two entries; a plain Literal["a"] produces a singleton set.
+# a frozenset of two entries; a plain Literal["a"] produces a length 1 set.
 LiteralFingerprint = dict[int, frozenset[tuple[type, LiteralValue]]]
 
 
-def literal_args_are_disjoint(fp1: LiteralFingerprint, fp2: LiteralFingerprint) -> bool:
-    """Return True if two overloads are provably disjoint via a Literal argument.
-
-    If there is any argument position where both carry only LiteralType values
-    and those value sets are disjoint, no single call can match both overloads
-    and the pairwise overlap check can be skipped entirely.
-    """
-    for idx, vals1 in fp1.items():
-        vals2 = fp2.get(idx)
-        if vals2 is not None and vals1.isdisjoint(vals2):
-            return True
-    return False
-
-
 def build_literal_fingerprint(sig: CallableType) -> LiteralFingerprint:
     """Build a LiteralFingerprint for one overload signature.
 
@@ -9033,6 +9006,20 @@ def build_literal_fingerprint(sig: CallableType) -> LiteralFingerprint:
     return fingerprint
 
 
+def literal_args_are_disjoint(fp1: LiteralFingerprint, fp2: LiteralFingerprint) -> bool:
+    """Return True if two overloads are provably disjoint via a Literal argument.
+
+    If there is any argument position where both carry only LiteralType values
+    and those value sets are disjoint, no single call can match both overloads
+    and the pairwise overlap check can be skipped entirely.
+    """
+    for idx, vals1 in fp1.items():
+        vals2 = fp2.get(idx)
+        if vals2 is not None and vals1.isdisjoint(vals2):
+            return True
+    return False
+
+
 def overload_can_never_match(signature: CallableType, other: CallableType) -> bool:
     """Check if the 'other' method can never be matched due to 'signature'.