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Copy pathprinting inputs by through function call using 2d array pointers
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87 lines (72 loc) · 1.66 KB
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printing inputs by through function call using 2d array pointers
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87 lines (72 loc) · 1.66 KB
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#include <stdio.h>
void f1(int (*q)[4], int rm, int cm) ;
void f2(int (*u)[4], int rm, int cm) ;
int main()
{
int a[3][4];
int (*p)[4] = a;
f1(p,3,4);
f2(p,3,4);
return 0;
}
void f1(int (*q)[4], int rm, int cm)
{
int i, j;
for (i = 0; i < rm; i++) {
printf("Enter four numbers: ");
for (j = 0; j < cm; j++)
{
scanf("%d", &q[i][j]);
}
}
}
void f2(int (*u)[4], int rm, int cm)
{
int i, j;
for (i = 0; i < rm; i++) {
for (j = 0; j < cm; j++)
{
printf("%d ", u[i][j]);
}
printf("\n");
}
}
/* important note: the 'q' pointer is used to access and modify the elements of the array pointed to by 'p'
To clarify,'(*q)[4]' in the parameter declaration int '(*q)[4]' indicates that q is a pointer to an array of size 4. It does not store the address of the p pointer itself, but rather it stores the address of the first element of the array (a[0]).
Note: when pointer has array A address, array A= p */
method 2
#include <stdio.h>
void f1(int (**q)[4], int rm, int cm) ;
void f2(int (**u)[4], int rm, int cm) ;
int main()
{
int a[3][4];
int (*p)[4] = a;
f1(&p,3,4);
f2(&p,3,4);
return 0;
}
void f1(int (**q)[4], int rm, int cm)
{
int i, j;
for (i = 0; i < rm; i++)
{
printf("Enter four numbers: ");
for (j = 0; j < cm; j++)
{
scanf("%d", &(*q)[i][j]);
}
}
}
void f2(int (**u)[4], int rm, int cm)
{
int i, j;
for (i = 0; i < rm; i++)
{
for (j = 0; j < cm; j++)
{
printf("%d ", (*u)[i][j]);
}
printf("\n");
}
}