From c4870a0324dabebd7d1ea33cb0e8593b5d3db45a Mon Sep 17 00:00:00 2001
From: okafordarlington98
 <281412446+okafordarlington98@users.noreply.github.com>
Date: Wed, 6 May 2026 17:23:49 +0200
Subject: [PATCH] solve js basic algorithm

---
 .vscode/settings.json |  3 ++
 index.js              | 69 ++++++++++++++++++++++++++++++++++++++++++-
 2 files changed, 71 insertions(+), 1 deletion(-)
 create mode 100644 .vscode/settings.json

diff --git a/.vscode/settings.json b/.vscode/settings.json
new file mode 100644
index 000000000..6f3a2913e
--- /dev/null
+++ b/.vscode/settings.json
@@ -0,0 +1,3 @@
+{
+    "liveServer.settings.port": 5501
+}
\ No newline at end of file
diff --git a/index.js b/index.js
index 6b0fec3ad..1cd5b31a5 100644
--- a/index.js
+++ b/index.js
@@ -1,7 +1,74 @@
 // Iteration 1: Names and Input
-
+/*
+1.1 Create a variable hacker1 with the driver's name.*/
+let hacker1 = "Darlington";
+//1.2 Print "The driver's name is XXXX".
+console.log ("The drivers name is ${hacker 1}");
+//1.3 Create a variable hacker2 with the navigator's name.
+let hacker2 = "Yena"
+//1.4 Print "The navigator's name is YYYY".
+console.log ("The drivers name is ${hacker 1}");
 
 // Iteration 2: Conditionals
+//2.1. Depending on which name is longer, print:
+let count= hacker1.length;
+console.log(count);
+
+let count1= hacker2.length;
+console.log(count1);
 
+if(count>count1) {
+    console.log(`The driver has the longest name, it has ${count}`);
+} else if(count1>count) {
+    console.log(`It seems that the navigator has the longest name, it has ${count1}`);
+} else{
+    console.log(`Wow, you both have equally long names ${count1}`);
+}
+//- The driver has the longest name, it has XX characters. or
+//- It seems that the navigator has the longest name, it has XX characters. or
+//- Wow, you both have equally long names, XX characters!.
 
 // Iteration 3: Loops
+// 3.1 Print the characters of the driver's name, separated by space, and in capital letters, i.e., "J O H N".
+// console.log(hacker1);
+let capitalDriver = hacker1.toUpperCase();
+console.log(capitalDriver);
+let splitcapDriver = capitalDriver.split("").join(" ");
+console.log(splitcapDriver);
+
+
+// 3.2 Print all the characters of the navigator's name in reverse order, i.e., "nhoJ".
+console.log(hacker2.split('').reverse().join(''));
+
+/*
+3.3 Depending on the lexicographic order of the strings, print:
+
+The driver's name goes first.
+Yo, the navigator goes first, definitely.
+What?! You both have the same name?
+*/
+
+let firstLetDri = hacker1.charAt(0);
+console.log(firstLetDri);
+let firstLetNav = hacker2.charAt(0);
+console.log(firstLetNav);
+
+if (firstLetDri < firstLetNav) {
+    console.log(`The driver's name goes first.`);
+} else if (firstLetDri > firstLetNav) {
+    console.log(`Yo, the navigator goes first, definitely.`);
+} else {
+    console.log(`What?! You both have the same name?`);
+}
+
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