same-frequency.js

/**This problem can be solved by converting the numbers into strings, and then counting the frequency of each character (digit) in each string. Once we have the frequency counts, we can compare them to see if they are the same. */
function sameFrequency(num1, num2) {
    let str1 = num1.toString();
    let str2 = num2.toString();

    if(str1.length !== str2.length) return false;

    let count1 = {};
    let count2 = {};

    for(let char of str1){
        count1[char] = (count1[char] || 0) + 1;
    }

    for(let char of str2){
        count2[char] = (count2[char] || 0) + 1;
    }

    for(let key in count1){
        if(count1[key] !== count2[key]) return false;
    }

    return true;
}

// Time Complexity - O(N + M)