|
| 1 | +package algo |
| 2 | + |
| 3 | +import ( |
| 4 | + "context" |
| 5 | + "testing" |
| 6 | + |
| 7 | + "github.com/specterops/dawgs/container" |
| 8 | + "github.com/specterops/dawgs/graph" |
| 9 | + "github.com/stretchr/testify/require" |
| 10 | +) |
| 11 | + |
| 12 | +// Test a simple chain of verticies. In this example, each vertex is its own SCC. |
| 13 | +// |
| 14 | +// Graph: |
| 15 | +// 0 -> 1 -> 2 -> 3 |
| 16 | +func TestSCC_Chain(t *testing.T) { |
| 17 | + var ( |
| 18 | + digraph = container.BuildCSRGraph(map[uint64][]uint64{ |
| 19 | + 0: {1}, |
| 20 | + 1: {2}, |
| 21 | + 2: {3}, |
| 22 | + }) |
| 23 | + |
| 24 | + ctx = context.Background() |
| 25 | + sccs, nodeToSCCIndex = StronglyConnectedComponents(ctx, digraph) |
| 26 | + expectedNodeToComponent = map[uint64]uint64{ |
| 27 | + 0: 3, |
| 28 | + 1: 2, |
| 29 | + 2: 1, |
| 30 | + 3: 0, |
| 31 | + } |
| 32 | + ) |
| 33 | + |
| 34 | + require.Equalf(t, 4, len(sccs), "expected 4 SCCs, got %d", len(sccs)) |
| 35 | + |
| 36 | + // Each SCC must contain exactly one node |
| 37 | + for component, members := range sccs { |
| 38 | + require.Equalf(t, uint64(1), members.Cardinality(), "SCC %d expected size 1, got %d", component, members.Cardinality()) |
| 39 | + } |
| 40 | + |
| 41 | + require.Equal(t, expectedNodeToComponent, nodeToSCCIndex) |
| 42 | +} |
| 43 | + |
| 44 | +// Test a simple cycle. In this example, there should be two disconnected components. |
| 45 | +// |
| 46 | +// Graph: |
| 47 | +// 0 -> 0 |
| 48 | +// 1 |
| 49 | +func TestSCC_SimpleCycle(t *testing.T) { |
| 50 | + var ( |
| 51 | + digraph = container.BuildCSRGraph(map[uint64][]uint64{ |
| 52 | + 0: {0}, // self‑loop component |
| 53 | + 1: {}, // isolated vertex – must be present as a key! |
| 54 | + }) |
| 55 | + |
| 56 | + ctx = context.Background() |
| 57 | + sccs, nodeToIdx = StronglyConnectedComponents(ctx, digraph) |
| 58 | + ) |
| 59 | + |
| 60 | + require.Equalf(t, 2, len(sccs), "expected 2 components, got %d", len(sccs)) |
| 61 | + |
| 62 | + // The self‑loop should be a component of size 1 (Tarjan treats it as strongly connected) |
| 63 | + require.Equalf(t, uint64(1), sccs[nodeToIdx[0]].Cardinality(), "self‑loop node not alone in its component") |
| 64 | + require.Equalf(t, uint64(1), sccs[nodeToIdx[1]].Cardinality(), "isolated node not alone in its component") |
| 65 | +} |
| 66 | + |
| 67 | +// Test two cycles with a bridge (a “figure‑8” graph). There should be one component that contains |
| 68 | +// all verticies. |
| 69 | +// |
| 70 | +// Graph: |
| 71 | +// 0 -> 1 -> 2 -> 3 |
| 72 | +// 1 -> 3 |
| 73 | +// 2 -> 3 |
| 74 | +// 3 -> 1 |
| 75 | +func TestSCC_FigureEight(t *testing.T) { |
| 76 | + var ( |
| 77 | + digraph = container.BuildCSRGraph(map[uint64][]uint64{ |
| 78 | + 0: {1}, |
| 79 | + 1: {2, 3}, |
| 80 | + 2: {0}, |
| 81 | + 3: {1}, |
| 82 | + }) |
| 83 | + |
| 84 | + ctx = context.Background() |
| 85 | + sccs, nodeToIdx = StronglyConnectedComponents(ctx, digraph) |
| 86 | + ) |
| 87 | + |
| 88 | + // The whole graph is one SCC with 4 members |
| 89 | + require.Equalf(t, 1, len(sccs), "expected 1 SCC, got %d", len(sccs)) |
| 90 | + require.Equalf(t, uint64(4), sccs[0].Cardinality(), "expected component size 4, got %d", sccs[0].Cardinality()) |
| 91 | + |
| 92 | + // All nodes must map to component 0. |
| 93 | + digraph.EachNode(func(node uint64) bool { |
| 94 | + if component, ok := nodeToIdx[node]; !ok || component != 0 { |
| 95 | + t.Fatalf("node %d expected in component 0, got %d (exists=%v)", node, component, ok) |
| 96 | + } |
| 97 | + |
| 98 | + return true |
| 99 | + }) |
| 100 | +} |
| 101 | + |
| 102 | +// Test component graph construction including edge deduplication and directionality. |
| 103 | +// |
| 104 | +// Graph: |
| 105 | +// 0 → 1 → 2 → 0 (cycle A) |
| 106 | +// 3 → 4 → 5 → 3 (cycle B) |
| 107 | +// 2 → 3 (bridge from A to B) |
| 108 | +func TestComponentGraph_EdgeDeduplication(t *testing.T) { |
| 109 | + var ( |
| 110 | + digraph = container.BuildCSRGraph(map[uint64][]uint64{ |
| 111 | + 0: {1}, |
| 112 | + 1: {2}, |
| 113 | + 2: {0, 3}, |
| 114 | + 3: {4}, |
| 115 | + 4: {5}, |
| 116 | + 5: {3}, |
| 117 | + }) |
| 118 | + |
| 119 | + ctx = context.Background() |
| 120 | + componentGraph = NewComponentGraph(ctx, digraph) |
| 121 | + ) |
| 122 | + |
| 123 | + // Expect exactly two components |
| 124 | + if len(componentGraph.componentMembers) != 2 { |
| 125 | + t.Fatalf("expected 2 components, got %d", len(componentGraph.componentMembers)) |
| 126 | + } |
| 127 | + |
| 128 | + // Component IDs are 0 and 1 (order depends on traversal) |
| 129 | + var outEdges []uint64 |
| 130 | + |
| 131 | + // Verify that the component digraph contains a *single* edge from component A to B |
| 132 | + componentGraph.Digraph().EachAdjacentNode(0, graph.DirectionOutbound, func(v uint64) bool { |
| 133 | + outEdges = append(outEdges, v) |
| 134 | + return true |
| 135 | + }) |
| 136 | + |
| 137 | + if len(outEdges) == 0 { |
| 138 | + // The edge could be reversed depending on which component got ID 0, so test both possibilities |
| 139 | + componentGraph.Digraph().EachAdjacentNode(0, graph.DirectionInbound, func(v uint64) bool { |
| 140 | + outEdges = append(outEdges, v) |
| 141 | + return true |
| 142 | + }) |
| 143 | + } |
| 144 | + |
| 145 | + require.Equalf(t, 1, len(outEdges), "expected exactly one inter‑component edge, got %v", outEdges) |
| 146 | + require.Equalf(t, uint64(1), outEdges[0], "expected exactly one inter‑component edge, got %v", outEdges) |
| 147 | + |
| 148 | + var ( |
| 149 | + startComp, _ = componentGraph.ContainingComponent(0) |
| 150 | + endComp, _ = componentGraph.ContainingComponent(5) |
| 151 | + ) |
| 152 | + |
| 153 | + // The component containing origin vertex 0 should reach component containing origin vertex 5 |
| 154 | + require.Truef(t, componentGraph.ComponentReachable(startComp, endComp, graph.DirectionOutbound), "expected component %d to reach component %d", startComp, endComp) |
| 155 | +} |
| 156 | + |
| 157 | +// Test histogram counting. |
| 158 | +// |
| 159 | +// Graph: |
| 160 | +// 0 -> 1 -> 2 -> 0 |
| 161 | +// 3 -> 4 -> 5 -> 3 |
| 162 | +// 6 -> 7 -> 8 -> 6 |
| 163 | +func TestComponentHistogram(t *testing.T) { |
| 164 | + var ( |
| 165 | + digraph = container.BuildCSRGraph(map[uint64][]uint64{ |
| 166 | + 0: {1}, |
| 167 | + 1: {2}, |
| 168 | + 2: {0}, |
| 169 | + 3: {4}, |
| 170 | + 4: {5}, |
| 171 | + 5: {3}, |
| 172 | + 6: {7}, |
| 173 | + 7: {8}, |
| 174 | + 8: {6}, |
| 175 | + }) |
| 176 | + |
| 177 | + ctx = context.Background() |
| 178 | + componentGraph = NewComponentGraph(ctx, digraph) |
| 179 | + componentHistogram = componentGraph.ComponentHistogram([]uint64{0, 1, 2, 3, 4, 5, 6, 7, 8}) |
| 180 | + ) |
| 181 | + |
| 182 | + require.Equalf(t, 3, len(componentHistogram), "expected 3 components, got %d", len(componentHistogram)) |
| 183 | + |
| 184 | + for _, count := range componentHistogram { |
| 185 | + require.Equalf(t, uint64(3), count, "each component should have count 3, got %d", count) |
| 186 | + } |
| 187 | +} |
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