fix: regression when setting raw value to empty string

Author: oriondean

README.md

@@ -107,7 +107,6 @@ Retrieves the options on the input
 
 ##### rawValue
 Retrieves the raw value of the input (numerical)
->>>>>>> 16f3800... feat: update README to reflect various changes to API and development workflows
 
 #### value
 Retrieves the formatted value of the input (string)

src/helpers.ts

@@ -144,11 +144,15 @@ export const allowedZero = (val: string, char: string, caretPos: number, options
     }
 };
 
-export const formattedToRaw = (formattedValue: string, options: IOptions): number => {
+export const formattedToRaw = (formattedValue: string, options: IOptions): number | undefined => {
     if (is.not.string(formattedValue)) {
         return NaN;
     }
 
+    if (!formattedValue.length) {
+        return undefined;
+    }
+
     // Number(...) accepts thousands ',' or '' and decimal '.' so we must:
 
     // 1. Remove thousands delimiter to cover case it is not ','
@@ -202,7 +206,7 @@ export const parseString = (str: string, options: IOptions): string => {
     // Need to ensure that delimiter is a '.' before parsing to number
     const normalisedNumber = formattedToRaw(parsed, options);
     // Then swap it back in
-    const adjusted = rawToFormatted(normalisedNumber * multiplier, options);
+    const adjusted = rawToFormatted((normalisedNumber || 0) * multiplier, options);
     const tooLarge = adjusted.indexOf("e") !== -1;
 
     if (tooLarge) {