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46.全排列.cpp
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84 lines (79 loc) · 1.43 KB
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/*
* @lc app=leetcode.cn id=46 lang=cpp
*
* [46] 全排列
*
* https://leetcode-cn.com/problems/permutations/description/
*
* algorithms
* Medium (78.21%)
* Likes: 1528
* Dislikes: 0
* Total Accepted: 401.4K
* Total Submissions: 513K
* Testcase Example: '[1,2,3]'
*
* 给定一个不含重复数字的数组 nums ,返回其 所有可能的全排列 。你可以 按任意顺序 返回答案。
*
*
*
* 示例 1:
*
*
* 输入:nums = [1,2,3]
* 输出:[[1,2,3],[1,3,2],[2,1,3],[2,3,1],[3,1,2],[3,2,1]]
*
*
* 示例 2:
*
*
* 输入:nums = [0,1]
* 输出:[[0,1],[1,0]]
*
*
* 示例 3:
*
*
* 输入:nums = [1]
* 输出:[[1]]
*
*
*
*
* 提示:
*
*
* 1
* -10
* nums 中的所有整数 互不相同
*
*
*/
// @lc code=start
class Solution {
public:
vector<vector<int>> ans;
vector<int> path;
vector<bool> st;
vector<vector<int>> permute(vector<int>& nums) {
path.resize(nums.size());
st.resize(nums.size());
dfs(nums,0);
return ans;
}
void dfs(vector<int>& nums, int u) {
if(u==nums.size()) {
ans.push_back(path);
return;
}
for(int i=0;i<nums.size();++i) {
if(st[i]==false) {
path[u]=nums[i];
st[i]=true;
dfs(nums,u+1);
st[i]=false;
}
}
}
};
// @lc code=end