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236.lowest-common-ancestor-of-a-binary-tree.cpp
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97 lines (82 loc) · 2.37 KB
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#include <iostream>
#include <vector>
using namespace std;
struct TreeNode
{
int val;
TreeNode *left;
TreeNode *right;
TreeNode(int x) : val(x), left(NULL), right(NULL) {}
};
class Solution
{
private:
int pVal, qVal;
vector<struct TreeNode *> v;
vector<struct TreeNode *> pAncestor;
vector<struct TreeNode *> qAncestor;
void preorderTraversal(TreeNode *node)
{
v.push_back(node);
if (node->val == pVal)
{
pAncestor = v;
}
if (node->val == qVal)
{
qAncestor = v;
}
if (node->left != NULL)
preorderTraversal(node->left);
if (node->right != NULL)
preorderTraversal(node->right);
v.pop_back();
}
public:
TreeNode *lowestCommonAncestor(TreeNode *root, TreeNode *p, TreeNode *q)
{
pVal = p->val;
qVal = q->val;
preorderTraversal(root);
TreeNode *result = NULL;
int i = pAncestor.size() - 1, j = qAncestor.size() - 1;
for (; i >= 0; i--)
{
for (int k = j; k >= 0; k--)
{
if (qAncestor[k]->val == pAncestor[i]->val)
{
result = qAncestor[k];
break;
}
}
if (result != NULL)
break;
}
return result;
}
};
int main(int argc, char const *argv[])
{
struct TreeNode *tree = new TreeNode(1);
struct TreeNode *treeLeft = new TreeNode(2);
struct TreeNode *treeRight = new TreeNode(3);
struct TreeNode *treeLeftLeft = new TreeNode(4);
struct TreeNode *treeLeftRight = new TreeNode(5);
struct TreeNode *treeRightLeft = new TreeNode(6);
struct TreeNode *treeRightRight = new TreeNode(7);
struct TreeNode *treeLeftRightLeft = new TreeNode(8);
struct TreeNode *treeLeftRightRight = new TreeNode(9);
tree->left = treeLeft;
tree->right = treeRight;
treeLeft->left = treeLeftLeft;
treeLeft->right = treeLeftRight;
treeRight->left = treeRightLeft;
treeRight->right = treeRightRight;
treeLeftRight->left = treeLeftRightLeft;
treeLeftRight->right = treeLeftRightRight;
Solution solution;
struct TreeNode *ancestor = solution.lowestCommonAncestor(tree, treeLeftRight, treeLeftRightRight);
cout << "ancestor: " << ancestor->val << endl;
return 0;
}