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105.construct-binary-tree-from-preorder-and-inorder-traversal.c
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70 lines (57 loc) · 1.63 KB
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#include <stdlib.h>
#include <stdio.h>
/**
* Definition for a binary tree node.
*/
struct TreeNode
{
int val;
struct TreeNode *left;
struct TreeNode *right;
};
struct TreeNode *buildTree(int *preorder, int preorderSize, int *inorder, int inorderSize)
{
if (preorderSize == 0 || inorderSize == 0)
return NULL;
struct TreeNode *root = (struct TreeNode *)malloc(sizeof(struct TreeNode));
root->val = preorder[0];
int leftTreeSize = 0, rightTreeSize = 0;
for (size_t i = 0; i < inorderSize; i++)
{
if (inorder[i] == root->val)
{
break;
}
leftTreeSize++;
}
rightTreeSize = inorderSize - leftTreeSize - 1;
int *leftTreePreorder = preorder + 1;
int *rightTreePreorder = preorder + 1 + leftTreeSize;
int *leftTreeInorder = inorder;
int *rightTreeInorder = inorder + leftTreeSize + 1;
root->left = buildTree(leftTreePreorder, leftTreeSize, leftTreeInorder, leftTreeSize);
root->right = buildTree(rightTreePreorder, rightTreeSize, rightTreeInorder, rightTreeSize);
return root;
}
void traversal(struct TreeNode *root)
{
if (root->left != NULL)
{
traversal(root->left);
}
if (root->right != NULL)
{
traversal(root->right);
}
printf("%d ", root->val);
}
int main(int argc, char const *argv[])
{
int preorder[] = {3, 9, 20, 15, 7};
int inorder[] = {9, 3, 15, 20, 7};
struct TreeNode *tree = buildTree(preorder, sizeof(preorder) / sizeof(preorder[0]),
inorder, sizeof(inorder) / sizeof(inorder[0]));
traversal(tree);
printf("\n");
return 0;
}