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binary_lifiting.cpp
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164 lines (133 loc) · 3.95 KB
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#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma")
#include <bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp> //required
//#include <ext/pb_ds/tree_policy.hpp> //required
//using namespace __gnu_pbds; //required
using namespace std;
//template <typename T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// ordered_set <int> s;
// s.find_by_order(k); returns the (k+1)th smallest element
// s.order_of_key(k); returns the number of elements in s strictly less than k
#define pb push_back
#define mp(x,y) make_pair(x,y)
#define all(x) x.begin(), x.end()
#define print(vec,l,r) for(int i = l; i <= r; i++) cout << vec[i] <<" "; cout << endl;
#define input(vec,N) for(int i = 0; i < (N); i++) cin >> vec[i];
#define debug(...) logger(#__VA_ARGS__, __VA_ARGS__)
#define leftmost_bit(x) (63-__builtin_clzll(x))
#define rightmost_bit(x) __builtin_ctzll(x) // count trailing zeros
#define set_bits(x) __builtin_popcountll(x)
#define pow2(i) (1LL << (i))
#define is_on(x, i) ((x) & pow2(i)) // state of the ith bit in x
#define set_on(x, i) ((x) | pow2(i)) // returns integer x with ith bit on
#define set_off(x, i) ((x) & ~pow2(i)) // returns integer x with ith bit off
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
// auto dist = uniform_int_distribution<int>(l, r);
// use int a = dist(rng) to get a random number between [l,r] inclusive
template<typename ...Args>
void logger(string vars, Args&&... values) {
cerr << vars << " = ";
string delim = "";
(..., (cerr << delim << values, delim = ", "));
cerr << endl;
}
typedef long long int ll;
typedef long double ld;
const int MOD = 1e9+7; // 998244353;
const ll INF = 1e18; // not too close to LLONG_MAX
const ld PI = acos((ld)-1);
const ld EPS = 1e-8;
const int dx[4] = {1,0,-1,0}, dy[4] = {0,1,0,-1}; // for every grid problem!!
// highly risky #defines
#define int ll // disable when you want to make code a bit faster
#define endl '\n' // disable when dealing with interactive problems
typedef vector<int> vi;
typedef pair<int, int> pii;
const int MAXN = 1e5+5;
int n, l; // = 1 + log2(MAXN);
vector<vector<int>> adj;
int timer;
vector<int> height, tin, tout;
vector<vector<int>> up;
void dfs(int v, int p){
tin[v] = ++timer;
up[v][0] = p;
height[v] = 1 + height[p];
for (int i = 1; i <= l; ++i)
up[v][i] = up[up[v][i-1]][i-1];
for (int u : adj[v]) {
if (u != p)
dfs(u, v);
}
tout[v] = ++timer;
}
bool is_ancestor(int anc, int v){
return tin[anc] <= tin[v] && tout[anc] >= tout[v];
}
int lca(int u, int v){
if (is_ancestor(u, v))
return u;
if (is_ancestor(v, u))
return v;
for (int i = l; i >= 0; --i) {
if (!is_ancestor(up[u][i], v))
u = up[u][i];
}
return up[u][0];
}
int lca_dist(int anc, int u){
assert(anc == lca(anc, u));
if(anc == u) return 0;
int ans = 1;
for (int i = l; i >= 0; --i) {
if (!is_ancestor(up[u][i], anc)){
u = up[u][i];
ans += pow2(i);
}
}
return ans;
}
int dist(int u, int v){
int anc = lca(u, v);
return lca_dist(anc, u) + lca_dist(anc, v);
}
void preprocess(int root) {
tin.resize(n);
tout.resize(n);
timer = 0;
l = ceil(log2(n));
up.assign(n, vector<int>(l + 1));
height.assign(n, -1);
dfs(root, root);
}
void solve(){
// code starts from here
int q;
cin >> n >> q;
adj.clear();
adj.resize(n);
height.assign(n, -1);
for(int u, v, i = 1; i < n; i++){
cin >> u >> v;
u--;v--;
adj[u].pb(v);
adj[v].pb(u);
}
preprocess(0); // usually 0 is root
for(int t, k, i = 0; i < q; i++){
cin >> t >> k;
t--;k--;
cout << dist(t, k) << endl;
}
}
signed main(){
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int T = 1;
// cin >> T;
while(T--){
solve();
}
return 0;
}