CONDITIONAL_STATEMENT.CPP

// largest of 2 no.
/*
#include<iostream>
using namespace std;
int main(){
    int a,b;
    cout<<"enter first number:";
    cin>>a;
    cout<<"enter second number:";
    cin>>b;
    if(a>b){
        cout<<"larger number is:"<<a<<endl;
    }
    else if(b>a){
        cout<<"larger number is:"<<b<<endl;
    }
    else{
        cout<<"both numbers are equal."<<endl;
    }
} 


// find no. is even or odd.
#include<iostream>
using namespace std;
int main(){
    int a;
    cin>>a;
    if(a%2==0){
        cout<<"number is even."<<endl;
    }
    else{
        cout<<"number is odd."<<endl;
    }
}


#include <iostream>
using namespace std;
int main(){
    int income;
    float tax;
    cout<<"enter your income (in lakh):";
    cin>>income;
    if(income<=1){
        tax = 0;
    }
    else if(income>1 && income<=5){
        tax = 0.2*income;
    }
    else if(income>5 && income<=10){
        tax = 0.3*income;
    }
    else{
        tax = 0.4*income;
    }
    cout<<"your tax is: "<<(tax*100000)<<endl;
}


// largest of 3 no.
#include <iostream>
using namespace std;
int main(){
    int a,b,c;
    cin>>a>>b>>c;
    if(a>b && a>c){
        cout<<"largest number is:"<<a<<endl;
    }
    else if(b>c && b>a){
        cout<<"largest number is:"<<b<<endl;
    }
    else if(c>a && c>b){
        cout<<"largest number is:"<<c<<endl;
    }
    else{
        cout<<"all numbers are equal."<<endl;
    }
    return 0;
}


// largest of 2 no. using ternary operator
#include <iostream>
using namespace std;
int main(){
    int a,b;
    cout<<"enter a and b:";
    cin>>a>>b;
    int largest = (a>b) ? a : b;
    cout<<"largest number is:"<<largest<<endl;
    return 0;
}



// build a simple calculator using switch case.
#include <iostream>
using namespace std;
int main(){
    char op;
    float num1,num2;
    cout<<"enter first number:";
    cin>>num1;
    cout<<"enter second number:";
    cin>>num2;
    cout<<"enter operator (+,-,*,/):";
    cin>>op;
    switch(op){
        case '+':
            cout<<"result is:"<<num1+num2<<endl;
            break;
        case '-':
            cout<<"result is:"<<num1-num2<<endl;
            break;
        case '*':
            cout<<"result is:"<<num1*num2<<endl;
            break;
        case '/':
            if(num2!=0){
                cout<<"result is:"<<num1/num2<<endl;
            }
            else{
                cout<<"division by zero is not allowed."<<endl;
            }
            break;
        default:
            cout<<"invalid operator."<<endl;
    }
    return 0;
}



// find the no. is positive, negative or zero.
#include <iostream>
using namespace std;
int main(){
    int a;
    cout<<"enter a number:";
    cin>>a;
    if(a>0){
        cout<<"number is positive."<<endl;
    }
    else if(a<0){
        cout<<"number is negative."<<endl;
    }
    else{
        cout<<"number is zero."<<endl;
    }
    return 0;
}


// For any 3 digit number check whether it’s an Armstrong number or not.
#include <iostream>
using namespace std;
int main(){
    int num, originalNum, remainder, result = 0;
    cout<<"enter a 3 digit number:";
    cin>>num;
    originalNum = num;
    while(num != 0){
        remainder = num % 10;
        result += remainder * remainder * remainder;
        num /= 10;
    }
    if(result == originalNum){
        cout<<"number is an Armstrong number."<<endl;
    }
    else{
        cout<<"number is not an Armstrong number."<<endl;
    }
    return 0;
}*/



// to find the no. is leap year or not.
#include <iostream>
using namespace std;
int main(){
    int year;
    cout<<"enter a year:";
    cin>>year;
    if((year%4==0 && year%100!=0) || (year%400==0)){
        cout<<"year is a leap year."<<endl;
    }
    else{
        cout<<"year is not a leap year."<<endl;
    }
    return 0;
}