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18_Reverse_Polish_Notation.java
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78 lines (56 loc) · 2.05 KB
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// You are given an array of strings tokens that represents an arithmetic expression in a Reverse Polish Notation.
// Evaluate the expression. Return an integer that represents the value of the expression.
// Note that:
// The valid operators are '+', '-', '*', and '/'.
// Each operand may be an integer or another expression.
// The division between two integers always truncates toward zero.
// There will not be any division by zero.
// The input represents a valid arithmetic expression in a reverse polish notation.
// The answer and all the intermediate calculations can be represented in a 32-bit integer.
// Example 1:
// Input: tokens = ["2","1","+","3","*"]
// Output: 9
// Explanation: ((2 + 1) * 3) = 9
// Example 2:
// Input: tokens = ["4","13","5","/","+"]
// Output: 6
// Explanation: (4 + (13 / 5)) = 6
// Example 3:
// Input: tokens = ["10","6","9","3","+","-11","*","/","*","17","+","5","+"]
// Output: 22
// Explanation: ((10 * (6 / ((9 + 3) * -11))) + 17) + 5
// = ((10 * (6 / (12 * -11))) + 17) + 5
// = ((10 * (6 / -132)) + 17) + 5
// = ((10 * 0) + 17) + 5
// = (0 + 17) + 5
// = 17 + 5
// = 22
// General approach and also optimal approach too
class Solution {
public int evalRPN(String[] tokens) {
Stack<Integer> st=new Stack<>();
for(String token:tokens){
switch(token){
case "+":
st.push(st.pop()+st.pop());
break;
case "-":
int b=st.pop();
int a=st.pop();
st.push(a-b);
break;
case "*":
st.push(st.pop()*st.pop());
break;
case "/":
int div = st.pop();
int dvd = st.pop();
st.push(dvd / div);
break;
default:
st.push(Integer.parseInt(token));
}
}
return st.pop();
}
}