Add all even numbers from an array.
Array:
[1, 2, 3, 4, 5, 6]
Result:
2 + 4 + 6 = 12
let numbers = [1, 2, 3, 4, 5, 6];
let sum = 0;
for (let i = 0; i < numbers.length; i++) {
if (numbers[i] % 2 === 0) {
sum += numbers[i];
}
}
console.log(sum);function isEven(n) {
return n % 2 === 0;
}
function addEvenNumbers(arr) {
let total = 0;
for (let i = 0; i < arr.length; i++) {
if (isEven(arr[i])) {
total += arr[i];
}
}
return total;
}
let numbers = [1, 2, 3, 4, 5, 6];
console.log(addEvenNumbers(numbers));let numbers = [1, 2, 3, 4, 5, 6];
let sum = numbers.filter((n) => n % 2 === 0).reduce((a, b) => a + b, 0);
console.log(sum);class NumberArray {
constructor(numbers) {
this.numbers = numbers;
}
isEven(n) {
return n % 2 === 0;
}
sumEvens() {
let total = 0;
for (let n of this.numbers) {
if (this.isEven(n)) {
total += n;
}
}
return total;
}
}
let nums = new NumberArray([1, 2, 3, 4, 5, 6]);
console.log(nums.sumEvens());